Question

Resolva a equação incompleta SEM USAR BHÁSKARA


(3x+1)^ +(x-2)(x+1) = -1

Answer 1

Resposta:

S = {- 1/2, 0}

Explicação passo-a-passo:

${(3x + 1)}^{2} + (x + 2)(x + 1) = - 1 \\ 9 {x}^{2} + 6x + 1 + {x}^{2} + x - 2x - 2 = - 1 \\ 9 {x}^{2} + {x}^{2} + 6x + x - 2x + 1 - 2 = - 1 \\ 10 {x}^{2} + 5x - 1 = - 1 \\ 10 {x}^{2} + 5x - \diagup\!\!\!\!1 + \diagup\!\!\!\!1 = 0 \\ 10 {x}^{2} + 5x = 0 \\ 5x \times (2x + 1) = 0 \: ( \div5 ) \\ x \times (2x + 1) = 0 \\ \\ \bf{x = 0} \\ \\ 2x + 1 = 0 \\ 2x = 0 - 1 \\ 2x = - 1 \\ \bf{x = - \frac{1}{2} }$