Question

resolva a equacao exponencial
$\sqrt[4]{2} ^{x - 1} = 8$

Answer 1

$\sqrt[4]{2}^{x-1}=8 \\ \\ 2^{\frac{x-1}{4}}=2^3 \\ \\ \frac{x-1}{4}=3 \\ \\ x=12+1 \\ \\ x=13$