Question

resolva a equação exponencial :
${27}^{ {x}^{2} + 1} = {9}^{5x}$

Answer 1

27^x^2x+1=9^5x <>3^3(2x+1)=3^2(5x) <> 3x^2+3=10x <>3x^2-10x+3 usando fórmula de Bhaskara x1/2=10+-8/2 <>x1=18/2=9 e x2=2/2 =1