Question

resolva a equação exponencial
$2 {}^{3x - 1 } = 32$
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Answer 1

Oi

Resolvendo ...

$2^{3x-1}=32\\\\\\\\2^{3x-1}=2^{5}\\\\\\\\3x-1=5\\\\\\\\3x=5+1\\\\\\\\3x=6\\\\\\\\x=\frac{6}{3} \\\\\\\\\boxed{\boxed{x=2}}\\\\\\\\\\Bons\ estudos!\ \ \ :)$

Answer 2

Resposta:

x = 2

Explicação passo-a-passo:

2³ˣ⁻¹ = 32

2³ˣ⁻¹ = 2⁵ ⇒elimina as bases iguais

3x - 1 = 5

3x = 5 + 1

3x = 6

x = 6/3

x = 2

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