Question

resolva a equação exponencial
9ˣ+¹= ³√243

Answer 1

${9}^{x + 1} = \sqrt[3]{243} \\ {( {3}^{2} )}^{x + 1} = {3}^{ \frac{7}{3} } \\ {3}^{2x + 2} = {3}^{ \frac{7}{3} } \\ 2x + 2 = \frac{7}{3} \\ 6x + 6 = 7 \\ 6x = 7 - 6 \\ 6x = 1 \\ x = \frac{1}{6}$