Question

resolva a equação exponencial: ∛7^x-2 = ^x√7^5

Answer 1

∛7^x-2 = ^x√7^5

7^(x-2/3) = 7^(5/x) => destrua a base

(x-2/3) = (5/x)

x.(x-2) = 5.3

x² -2x -15 = 0

∆= (-2)² -4.1.(-15)= 4 +60=64 ==>√∆=8

x = -b±√∆/2a

x = 2±8/2.1

x' = 2+8/2 =10/2= 5 ✓

x" = 2-8/2 = -6/2 = -3 ✓