Question

Resolva a equação exponencial​

Answer 1

$2^{3x-1}\cdot4{2x+3}=8^{3-x}\\\\2^{3x-1}\cdot(2^2)^{2x+3}=(2^3)^{3-x}\\\\2^{3x-1}\cdot2^{4x+6}=2^{9-3x}\\\\2^{3x-1+4x+6}=2^{9-3x}\\\\2^{7x+5}=2^{9-3x}\\\\\\7x+5=9-3x\\\\7x+3x=9-5\\\\10x=4\\\\x=\frac{4^{:2}}{10_{:2}}\\\\x=\frac{2}{5}\\\\S=\big\{\frac{2}{5}\big\}$