Question

resolva a equaçao exponencial

(2^x)^x+1 = 64

Answer 1

Oi Wordsecret

(2^x)^(x + 1) = 64

2^(x² + x) = 64

2^(x² + x) = 2^6 

x² + x = 6
x² + x - 6 = 0

delta
d² = 1 + 24 = 25
d = 5

x1 = (-1 + 5)/2 = 4/2 = 2
x2 = (-1 - 5)/2 = -6/2 = -3

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