Question

resolva a equação exponencial 2 vezes 2 elevado a x = raiz de 8 x raiz quarta raiz 4 de 2 vezes raiz 6de 2?????​

Answer 1

$2.{2}^{x}=\sqrt{8}.\sqrt[4]{2}.\sqrt[6]{2}$

${2}^{x+1}=\sqrt{{2}^{3}}. \sqrt[4]{2}.\sqrt[6]{2}$

${2}^{x+1}={2}^{\frac{3}{2}}.{2}^{\frac{1}{4}}.{2}^{\frac{1}{6}}$

${2}^{x+1}={2}^{\frac{3}{2}+\frac{1}{4}+\frac{1}{6}}$

${2}^{x+1}={2}^{\frac{18+3+2}{12}}$

${2}^{x+1}={2}^{\frac{23}{2}}$

$x+1=\frac{23}{2}$

$2x+2=23 \\ 2x=23-2 \\ 2x=21$

$\boxed{\boxed{x=\frac{21}{2}}}$

Answer 2

Resposta:

x+1=23/2

fiz no papel, deu isso