Question

Resolva a equação exponencial(2/7)x2-3=(49/4)x

Answer 1

              $(\frac{2}{7} ) ^{x^2-3} = (\frac{49}{4} ) ^{x} \\ \\ (\frac{2}{7}) ^{x^2-3}= [(\frac{7}{2} )^2]^x \\ \\ ( \frac{2}{7}) ^{x^2-3} =( \frac{2}{7} ) ^{-2x} \\ \\ x^2-3=-2x \\ \\ x^2+2x-3=0 \\ \\ (x+3)(x-1)=0 \\ \\ x+3=0 \\ x1=-3 \\ \\ x-1=0 \\ x2=1$
 
                              S = {-3, 1}