Question

resolva a equação do 2o grau: 
$x^{2}$-7x+10=0

Answer 1

$Resolu\c{c}\~ao\to \left\{\begin{array}{ccc}x^2-7x+10 = 0\\\\\Delta =b^2-4ac = (-7)^2-4*(1)*(10) = 49-40 = 9\\\\x = \frac{-b\pm \sqrt{\Delta}}{2a} = \frac{7\pm3}{2} \left \{ {{x'= \frac{7+3}{2} = 5 } \atop {x''= \frac{7-3}{2} = 2}}\\\\\boxed{\boxed{S=\{2,5\}}} \right. \end{array}\right$

Espero ter ajudado. :))

Answer 2

x² - 7x + 10 = 0
Δ = b² - 4 . a . c
Δ = (- 7)² - 4 . 1 . 10
Δ = 49 - 40
Δ = 9

x = (- b ± √Δ)/(2 . a)
x = (- (- 7) ± √9)/(2 . 1)
x = (7 ± 3)/2

x' = (7 + 3)/2
x' = 10/2
x' = 5

x'' = (7 - 3)/2
x'' = 4/2
x'' = 2

S = {2, 5}