Question

resolva a equaçao do 2°grau sendo U = IR x²- 3x + 2=0

Answer 1

Bhaskara :D 
Delta = b^2 - 4 a c 
D = (-3)^2 - 4 .  1 . 2 
D = 9 - 8
D = 1 

x1 = 3 + 1/ 2. 1 
x1 = 4/2 =  2

x2 = 3 -1 / 2 
x2 = 2/2 = 1