Question

resolva a equação do 2°grau completa x²-4x-12=0,sendo u=R​

Answer 1

$x^{2}-4x-12=0$

$\Delta =(-4)^{2}-4.1.(-12) = 64$

$x_1 = \dfrac{-(-4)+8}{2.1}=6$

$x_2 = \dfrac{-(-4)-8}{2.1}=-2$

Answer 2

x²- 4x-12=0

a = 1  b = -4  c = -12

Δ = -4² - 4 . 1 . (-12)

Δ = 16 + 48

Δ = 64

X = - (-4) ± √64 / 2.1

X = 4 ± 8 / 2

X¹ = 4 + 8 / 2 = 12/2 = 6

X² = 4 - 8 / 2 = -4/2 = -2

S = { -2, 6}