Question

resolva a equação do 2° grau.a) x²-5x+6=0 .b) x²-8x+12=0

​

Answer 1

Resposta:

Explicação passo-a-passo:

a) x²-5x+6=0 => Δ=b² - 4ac => Δ=(-5)² - 4(1)(6) => Δ= 25 - 24 =>  Δ= 1

x = -b ±√Δ/2a => x = 5 ±√1/2(1) => x = 5 ± 1/2 =>$x_{1} = \frac{5 +1}{2}=> x_{1} = \frac{6}{2}=>x_{1} = 3\\x_{2} = \frac{5 -1}{2}=> x_{2} = \frac{4}{2}=>x_{2} = 2$

b) x²-8x+12=0Δ=b² - 4ac => Δ=(-8)² - 4(1)(12) => Δ= 64 - 48 =>  Δ= 16

x = -b ±√Δ/2a => x = 8 ±√16/2(1) => x = 8 ± 4/2

=>$x_{1} = \frac{8 +4}{2}=> x_{1} = \frac{12}{2}=>x_{1} = 6\\x_{2} = \frac{8 -4}{2}=> x_{2} = \frac{4}{2}=>x_{2} = 2$