Question

resolva a equaçao do 2 grau
(x+1)(x+2)-2(x-3)=10

Answer 1

$(x+1)(x+2)-2(x-3)=10 \\ x^2+2x+x+2-2x+6-10=0 \\ x^2+x-2=0 \\ \Delta=1^2-4.1.(-2)=1+8=9 \\ x_1=\frac{-1-3}{2}=\frac{-4}{2}=-2 \\ x_2=\frac{-1+3}{2}=\frac{2}{2}=1 \\ S= \{-2,1 \}$