Question

resolva a equação do 2 grau; w² -11w+18=0 ?

Answer 1

w² -11w +18=0

a=1
b=-11
c=18

Δ=b²-4ac
Δ=(-11)²-4(18)
Δ=121-72
Δ=49
√Δ=√49 =±7

$w=- \frac{b\pm \sqrt{\triangle} }{2a} = \frac{-(-11)\pm \sqrt{49} }{2} = \frac{11\pm7}{2} \\ \\ w'= \frac{11+7}{2} = \frac{18}{2} =9 \\ \\ w"= \frac{11-7}{2} = \frac{4}{2} =2$

raízes são (2,9)