Question

resolva a equação de segundo grau:
x^2+2x-15= 0

Answer 1

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Na forma padrão, identifique "a", "b" e "c" da equação original e adicione esses valores à função do segundo grau.

2

+

2

−

1

5

=

0

x^{2}+2x-15=0

x2+2x−15=0

=

1

a={\color{#c92786}{1}}

a=1

=

2

b={\color{#e8710a}{2}}

b=2

=

−

1

5

c={\color{#129eaf}{-15}}

c=−15

=

−

2

±

2

2

−

4

⋅

1

(

−

1

5

)

√

2

⋅

1

x=\frac{-{\color{#e8710a}{2}} \pm \sqrt{{\color{#e8710a}{2}}^{2}-4 \cdot {\color{#c92786}{1}}({\color{#129eaf}{-15}})}}{2 \cdot {\color{#c92786}{1}}}

x=2⋅1−2±22−4⋅1(−15)​​

2

Simplifique

3

Separe as equações

4

Resolva

Solução

=

3

=

−

5

x=3\\x=-5

x=3x=−5

espero ter ajudado