Question

resolva a equação biquadrada x4_13x2+36=0

Answer 1

Ola Tauane

x⁴ - 13x² + 36 = 0

y = x²

y² - 13y + 36 = 0

delta
d² = 169 - 144 = 25
d = 5

y1 = (13 + 5)/2 = 18/2 = 9
y2 = (13 - 5)/2 = 8/2 = 4 

x1 = -3, x2 = 3, x3 = -2, x3 = 2

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Answer 2

x²=y

y² - 13y + 36 = 0
Δ = 169 -144
= 25

y' = (13 + √25) / 2 = (13+5)/2 = 9

y'' = (13 - √25)/2 = (13-5)/2 = 4

x² = y' e x² = y''
x² = 9
x = +3;-3
 x² = 4
x = +2;-2

S:{-3,-2,2,3}