Question

resolva a equacao biquadrada 2x^4+5x²-2=0

Answer 1

2x⁴+5x²-2=0

usando x² = t
2t²+5t-2=0

usando báskara
t = -5+-sqrt(5²-4.2.(-2) / 2.2
t1 = -5+sqrt(41) / 4
t2 = -5-sqrt(41) / 4

voltando ao original x² = t
x² = -5+sqrt(41) / 4
x² = -5-sqrt(41) / 4

x = +-sqrt(-5+sqrt(41) / 4)
x = +-sqrt(-5-sqrt(41) / 4)

x1 = sqrt(-5+sqrt(41)) / 2
x2 = -sqrt(-5-sqrt(41)) / 2