Question

Resolva a equação abaixo:

pfvr me ajudem, logaritmo é dificil pra mim​

Answer 1

resolva:

log2 (x-2) + log2 (x-3) = 1 + log2 (2x-7)

log2 (x-2)•(x-3) = log2 2 + log2 (2x-7)

log2 (x-2)•(x-3) = log2 2• (2x-7)

(x-2)•(x-3) = 2• (2x-7)

x² -5x +6 = 4x -14

x² -9x +20 = 0

∆= b² -4ac = 81 -4 1.20 = 1 => √∆=1

x' = -b+√∆/2a = 9+1/2 = 10/2 = 5 ✓

x" = -b-√∆/2a = 9-1/2 = 8/2 = 4 ✓