Question

Resolva a equação abaixo:

Answer 1

 $\frac{(n+1)!}{(n-1)!((n+1 - n +1)!} + 2 \frac{n!}{n!(n-(n-2)!} = 22 \\ \frac{(n+1)!}{(n-1)!(2)!} + 2 \frac{n!}{n!(2)!} = 22 \\ \frac{(n+1)(n)(n-1)!}{(n-1)!(2!)} + 2 \frac{1}{2} = 22 \\ \frac{(n+1).n}{2} + 1 = 22 \\ \frac{(n+1).n}{2} = 22 - 1 \\ (n+1).n = 42 \\ n^{2} +n = 42 \\ n(n+1) = 42 \\ n = 0 \\ ou \\ n + 1 = 42 \\ n = 41$

Espero ter ajudado