Matemática, perguntado por IsabelaMendes256, 1 ano atrás

Resolva a Equação
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Anexos:

Soluções para a tarefa

Respondido por nightblade
0
B)  \frac{3x}{4} - (- \frac{x}{3} = 5
MMC de 3 e 4 = 12
 \frac{9x}{12} - (- \frac{4x}{12} ) = 5
 \frac{13x}{12} = 5
13x = 5 · 12
13x = 60
x =  \frac{60}{13}

C)  \frac{x}{5} - (-1) = 9
 \frac{x}{5} + 1 = 9
 \frac{x}{5} = 9 - 1
x = 8 · 5 
x = 40

D) 
 \frac{x}{3} - (-5) = 0
 \frac{x}{3} = 0 - 5
x = -5 · 3
x = -15

E)  \frac{x}{2} -  \frac{3x}{5} = 6
MMC de 2 e 5 = 10
 \frac{5x}{10} -  \frac{6x}{10} = 6
 \frac{-1x}{10} = 6
- x = 6 · 10
x = -60

F)  \frac{x}{5} -  \frac{x}{2} =  \frac{7}{10}
 \frac{2x}{10} -  \frac{5x}{10} =  \frac{7}{10}
-  \frac{3x}{10} =  \frac{7}{10}
-3x =  \frac{7}{10}  · 10
-3x =  \frac{7}{10}  ·  \frac{100}{10}
-3x =  \frac{700}{10}
-3x = 70
x =  \frac{-70}{3}

G) 5x - 10 =  \frac{x + 1}{2}
-10 - 1 =  \frac{-5x + x}{2}
11 =  \frac{4x}{2}
11 = 2x
x =  \frac{11}{2}

H)  \frac{8x - 1}{2} - 2x = 3
 \frac{8x}{2} - 2x = 3 + 1
4x - 2x = 4
2x = 4
x =  \frac{4}{2}
x = 2

I)  \frac{2x - 7}{5} =  \frac{x - 2}{3}
 \frac{2x}{5} - x =  \frac{-2}{3} + 7
 \frac{2x}{5} -  \frac{5x}{5} =  \frac{-2}{3} +  \frac{21}{3}
 \frac{-3x}{5} =  \frac{19}{3}
3x = -  \frac{19}{3}  · 5
3x =  \frac{19}{3} ·  \frac{15}{3}
3x =  \frac{195}{3}
3x = 65
x =  \frac{65}{3}

J)  \frac{5x}{2} = 2x +  \frac{x + 2}{3}
 \frac{5x}{2}  - 2x - x =   \frac{2}{3}  
  \frac{5x}{2}  -   \frac{4x}{2}  -   \frac{2x}{2}   =   \frac{2}{3}  
  \frac{-x}{2}  =   \frac{2}{3}  
-x =  \frac{2}{3}  · 2
x = - \frac{2}{3}  ·  \frac{6}{3}
x = - \frac{12}{3}
x = -4

K)  \frac{x - 3}{4} -  \frac{2x - 1}{5} = 5
MMC de 4 e 5 = 20
 \frac{5x - 15}{20} -  \frac{8x - 4}{20} = 5
 \frac{13x - 19}{20} = 5
 \frac{13x}{20} = 5 + 19 
13x = 24 · 20
13x = 480
x =  \frac{480}{13}

L)  \frac{x - 1}{2} +  \frac{x - 3}{3} = 6
 \frac{3x - 3}{6} +  \frac{2x - 6}{6} = 6
 \frac{5x - 9}{6} = 6
 \frac{5x}{6}  = 6 + 9
 \frac{5x}{6}  = 15
5x = 15 · 6 
5x = 90
x =  \frac{90}{5}  
x = 18


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