Question

resolva a equação a seguir usando a formula de bhaskara

x^2+6x-5=0

Answer 1

x²+6x-5=0
x={-(6)±√[6²-4.1.(-5)]}/2.1
x={-6±√[36+20]}/2
x={-6±√56}/2
x={-6±7,5}/2

x'=(-6+7,5)/2
x'=1,5/2
x'=0,75

x"=(-6-7,5)/2
x"=-13,5/2
x"=-6,75

x=(0,75;-6,75)

Answer 2

x² + 6x - 5 = 0

A= 1

B= 6

C= - 5

∆= b² - 4ac

∆= 6² - 4 • 1 • ( - 5)

∆= 36 + 20

∆= 56

x= - b ± √∆ / 2a

x= - 6 ± √56/2 • 1

x'= - 6 + √56/2

x''= - 6 - √56/2