Question

Resolva a equação A =
[₂ ₃ -₂]
[ ₀ ₁ ₓ] = ₂
[ ₂ ₓ ₋₃]

Answer 1

$\begin{bmatrix}2&3&-2\\0&1&x\\2&x&-3\end{bmatrix}=-2$

$\mathsf{2(-3-{x}^{2})-3(-2x)-2(-2)=-2}\\\mathsf{-6-2{x}^{2}+6x+4+2=0}\\\mathsf{-2{x}^{2}+6x=0\div(-2)}\\\mathsf{{x}^{2}-3x=0}$

$x(x - 3) = 0 \\ x = 0 \\ x - 3 = 0 \to \: x = 3$