Question

Resolva a equação : 8^1/3 + 16^1/4 + (-2)^2 -9^1/2 .

Answer 1

Vamos Lá ! 

$8^{ \frac{1}{3} } + 16^{ \frac{1}{4} } + (-2 )^{2} - 9^{ \frac{1}{2} }$



$\sqrt[3]{8} \ + \sqrt[4]{16}\ \ +\ (-2).(-2)\ - \ \sqrt[2]{9}$



$2\ \ +\ \ 2\ \ +\ \ 4\ \ -\ \ 3$



$4\ \ +\ \ 1\ \ =\ \ \boxed{\boxed{5}} \ \ \ \ \ \ \ \ \ \ \ \ \ \ ok$

Answer 2

$8^{ \frac{1}{3}} + 16^{ \frac{1}{4}} + (-2)^2 -9^{ \frac{1}{2}}= \\ \\ (2^3)^{ \frac{1}{3}} + (2^4)^{ \frac{1}{4}} + (-2)^2 -(3^2)^{ \frac{1}{2}}= \\ \\ (2)^{ \frac{3}{3}} + (2)^{ \frac{4}{4}} + (-2)^2 -(3)^{ \frac{2}{2}}= \\ \\ (2) + (2) + (-2)^2 -(3)= \\ \\ 2 +2 + 4-3= \boxed{5}$