Question

Resolva a equação 4(x-3)+40=64-3(x-2)

Answer 1

$\mathsf{4(x-3)+40=64-3(x-2)}\\\mathsf{4x-12+40=64-3x+6}\\\mathsf{4x+3x=64-40+6+12}\\\mathsf{7x=42}\\\mathsf{x=\dfrac{42}{7}=6}$