Question

Resolva a equação 36x2-12x+1=0

Answer 1

Resposta:

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~36x^{2}-12x+1=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=36{;}~b=-12~e~c=1\\\\\Delta=(b)^{2}-4(a)(c)=(-12)^{2}-4(36)(1)=144-(144)=0\\\\x^{'}=x^{''}=\frac{-(b)\pm\sqrt{\Delta}}{2(a)}=\frac{-(-12)\pm\sqrt{0}}{2(36)}=\frac{12\pm0}{72}=\frac{12\div12}{72\div12}=\frac{1}{6}\\\\S=\{\frac{1}{6},~\frac{1}{6}\}$