Question

Resolva a equação 2y²-3y-2=0

Answer 1

$2y^2-3y-2=0 \\ \\ \Delta = (-3)^2 - 4.2.(-2) \\ \Delta = 25 \\ \\ x = \frac{-(-3) \pm \sqrt{25} }{2.2} = \frac{3 \pm 5}{4} \\ \\ x' = \frac{3 + 5}{4} = 2 \\ \\ x'' = \frac{3-5}{4} = - \frac{2}{4} = - \frac{1}{2} \\ \\ \boxed{S = \{- \frac{1}{2};2\}}$