Question

Resolva a equaçao
2X²-5X+1=0

Delta
e
Bhaskara

Answer 1

Δ= (-5)²-4.2.1
Δ= 25-8
Δ= 17

x'= 5+√7/4
x''=5-√7/4

Beleza?

Answer 2

2x² - 5x + 1 = 0


delta = b² - 4.a.c


a = 2
b = -5
c = 1

delta = (-5)² - 4.2.1
delta = 25 - 8
delta = 17


x = -b ± √delta/2.a

x = -(-5) ± √17/2.2

x = (5 + √17)/4

x = (5 - √17)/4


s={ (5 + √17)/4, (5 - √17)/4 }