Question

resolva a equação 2x²-3x-4=1 , O produto das raizes encontradas é ?

Answer 1

$2x^2-3x-4=1\\2x^2-3x-5=0\\\Delta=b^2-4ac=9-4(2)(-5)=9+40=49\\x=\frac{-b\pm\sqrt{\Delta}}{2a}\\x=\frac{3\pm\sqrt{49}}{2(2)}\\x'=\frac{3+7}{4}=\frac{5}{2}\\x''=\frac{3-7}{4}=\frac{-4}{4}=-1\\\\x'.x''=\frac{-5}{2}.(-1)=\boxed{\frac{5}{2}}$