Question

resolva a equação 10x²-19x+6=0​

Answer 1

10x^2 - 19x + 6 = 0

a = 10

b = -19

c = 6

Δ = b^2 - 4 . a . c

Δ = (-19)^2 - 4 . 10 . 6

Δ = 361 - 40 . 6

Δ = 361 - 240

Δ = 121

x = -b ± √Δ /2 . a

x = - (-19) ± √121 /2 . 10

x = 19 ± 11 /20

x' = 19 + 11 /20

x' = 30/20

x' = 3/2

x"= 19 - 11 /20

x" = 8/20

x" = 2/5

S = { 3/2 , 2/5 }