Question

Resolva a equação: [− 1 3 1 − 2 x + 4 x 1 0 x] = 0

Answer 1

Diagonal principal

[-1 . (x+4) . x ] + [ 3 . x . 1] + [ -2 . 0 . 1]

[ -1 . ( x² + 4x)] + 3x + 0

- x² - 4x + 3x

- x² - x

Diagonal secundária

[1. 1. (x+4)] + [ 3. - 2 . x ] + [ x . 0 . -1]

x + 4 - 6x + 0

- 5x + 4

Dp - Ds = 0

( - x² - x ) - ( - 5x + 4) = 0

- x² - x + 5x - 4 = 0

- x² + 4x - 4 = 0

$\frac{ - 4 \frac{ + }{ - } \sqrt{16 - 16} }{ - 2}$

$\frac{ - 4 \frac{ + }{ - }0 }{ - 2}$

x' = -4/ -2 = 2

Answer 2

Resposta:

X'=-4/-2=2 valeu mano tamo junto