Question

Resolva:

a)3y/8-5/6=y/3-5/2
b)k+3=k-1/2
c)2(w-5)=3w-2
5 2

Answer 1

Resolva:

a)
3y/8-5/6=y/3-5/2
$9y - 20 = 8y - 60 \\ \\ 9y - 8y = - 60 + 20 \\ \\ y = - 40$
b)
k+3=k-1/2
$3 = - \frac{1}{2} \\ k \: \: pertence \: a \: 0$

c)2(w-5)=3w-2
5 2

$\frac{2(w - 5)}{5} = \frac{3w - 2}{2} \\ \\ \frac{2w - 10}{5} = \frac{3w - 2}{2} \\ \\ 2.(2w - 10) = 5.(3w - 2) \\ \\ 4w - 20 = 15w - 10 \\ \\ 4w - 15w = - 10 + 20 \\ \\ - 11w = 10 \\ \\ w = - \frac{10}{11}$