Question

Resolva :

a)3x²/5=0

b)3x(x+2)=6x

Answer 1

$\mathtt{3x^2/5 = 0} \\ \mathtt{3x^2 = 0 \times 5 } \\ \mathtt{3x^2 = 0} \\ \mathtt{x^2 = 0 \div3} \\ \mathtt{x = \sqrt{0}} \\ \mathtt{x = 0} \\ \\ \mathtt{3x(x+2)=6x} \\ \mathtt{3x^2 + 6x = 6x} \\ \mathtt{3x^2 + 6x -6x = 0} \\ \mathtt{3x^2 = 0} \\ \mathtt{x^2 = 0 \div3} \\ \mathtt{x = \sqrt0} \\ \mathtt{x = 0}$