Resolva:
A) 18/7 + 1/3 - 3/5
B) 3/8 + 7/8 - 5/8
C) 7/6 + 4/6 - 5/6 + 3/6 - 9/6
D) 1/10 + 7/10 - 3/10
E) 7/5 - 3/15 - 2/15
Soluções para a tarefa
Respondido por
1
18/7 + 1/3 - 3/5
mmc = 105
( 270 + 35 - 63)/105= 242/105 = 2 inteiros 32/105 ****
b
3/8 + 7/8 - 5/8 =
denominadores iguais só resolve os numeradores
( 3 + 7 - 5)/8 = 5/8 ****
c
1/10
7/6 + 4/6 - 5/6 + 3/6 - 9/6 )
só resolve os numeradores
( 7 + 4 + 3 - 5 - 9)/6 = ( 14 - 14 )/6 0/6 = zero ***
d
1/10 + 7/10 - 3/10
( 1 + 7 - 3 )/10 = ( 8 - 3)/10 = 5/10 = 1/2 ***
e
7/5 - 3/15 - 2/5
mmc = 15
( 21 - 3 - 6 )/15 = ( 21 - 9 )/15 = 12/15 = 4/5 ***
mmc = 105
( 270 + 35 - 63)/105= 242/105 = 2 inteiros 32/105 ****
b
3/8 + 7/8 - 5/8 =
denominadores iguais só resolve os numeradores
( 3 + 7 - 5)/8 = 5/8 ****
c
1/10
7/6 + 4/6 - 5/6 + 3/6 - 9/6 )
só resolve os numeradores
( 7 + 4 + 3 - 5 - 9)/6 = ( 14 - 14 )/6 0/6 = zero ***
d
1/10 + 7/10 - 3/10
( 1 + 7 - 3 )/10 = ( 8 - 3)/10 = 5/10 = 1/2 ***
e
7/5 - 3/15 - 2/5
mmc = 15
( 21 - 3 - 6 )/15 = ( 21 - 9 )/15 = 12/15 = 4/5 ***
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