Question

Resolva:

A) (1/9+6/15÷3/5)²
B)(7/8÷1/4+1/2)⁴
C)(3/4.8/3-5/12÷10/3)²

Me ajudem pfvr

Answer 1

Resposta:

Explicação passo-a-passo:

Olá...

a) $(\frac{1}{9} + \frac{6}{15} : \frac{3}{5})^{2}$ =

$(\frac{1}{9} + \frac{2}{5} : \frac{3}{5})^{2}$ =

$(\frac{1}{9} + \frac{2}{5} . \frac{5}{3})^{2}$ =

$(\frac{1}{9} + 2 . \frac{1}{3})^{2}$ =

$( \frac{1}{9} + \frac{2}{3})^{2}$ =

$(\frac{1 + 6}{9})^{2}$ =

$(\frac{7}{9})^{2}$ =

$\frac{49}{81}$

B) $(\frac{7}{8} : \frac{1}{4} + \frac{1}{2})^{4}$ =

$(\frac{7}{8} . \frac{4}{1} + \frac{1}{2})^{4}$ =

$( \frac{7}{2} . 1 + \frac{1}{2})^{4}$ =

$(\frac{7}{2} + \frac{1}{2})^{4}$ =

$(\frac{8}{2})^{4}$ =

$(4)^{4}$ =

$256$

C) $(\frac{3}{4} . \frac{8}{3} - \frac{5}{12} : \frac{10}{3})^{2}$ =

$( 1 . 2 - \frac{5}{12} . \frac{3}{10})^{2}$ =

$(2 - \frac{1}{4} . \frac{1}{2})^{2}$ =

$(2 - \frac{1}{8})^{2}$ =

$(\frac{16 - 1}{8})^{2}$ =

$(\frac{15}{8})^{2}$ =

$\frac{225}{64}$

espero ter ajudado!