Question

Resolva:

a) 1-(1/3)³ : 1/2 -1)²

b) (5- 1/2)² : (1/2 - 2)³

c) (0,1 + 1/5) : (-0,02 + 1/100)

d) (1/5 - 1/2) - (1/3 - 1/4) × 2/5

e) -5/8 + 1/4 × (0,2) + 1/2

Me ajudem pfv eu vou dar 20 pontos

Answer 1

Resposta:

$a)\\ \\(1-\frac{1}{3})^{2}:(\frac{1}{2}-1)^{2}=[1^{2}-2.1.\frac{1}{3}+(\frac{1}{3})^{2}]:[(\frac{1}{2})^{2}-2.\frac{1}{2}.1+1^{2}]=\\ \\(1-\frac{2}{3}+\frac{1}{9}):(\frac{1}{4}-1+1)=\frac{9-6+1}{9}:\frac{1}{4}=\frac{4}{9}:\frac{1}{4}=\\ \\\frac{4}{9}.\frac{4}{1}=\frac{16}{9}$

$b)\\ \\(5-\frac{1}{2})^{2}:(\frac{1}{2}-2)^{3}=\\ \\(5^{2}-2.5.\frac{1}{2}+(\frac{1}{2})^{2}):(\frac{1}{2})^{3}-3.(\frac{1}{2})^{2} .2+3.\frac{1}{2}.2^{2}-2^{3}=\\ \\(25-\frac{10}{2}+\frac{1}{4}):(\frac{1}{8}-3.\frac{1}{4}.2+3.\frac{1}{2}.4-8)=\\ \\\frac{100-20+1}{4}:\frac{1}{8}-\frac{6}{4}+\frac{12}{2}-8=\\ \\\frac{81}{4}:\frac{1}{8}-\frac{3}{2}+6-8=\\ \\\frac{81}{4}:(\frac{1}{8}-\frac{3}{2}-2)=\\ \\\frac{81}{4}:\frac{1-12-16}{8}=\\ \\\frac{81}{4}:-\frac{27}{8}=\frac{81}{4}.-\frac{8}{27}=-\frac{648}{108}$

648 ÷ 108 = 6

$c)\\ \\(0,1+\frac{1}{5}):(0,02+\frac{1}{100})=(\frac{1}{10}+\frac{1}{5}):(-\frac{2}{100}+\frac{1}{100})=\\ \\\frac{1+2}{10}:-\frac{2+1}{100}=\frac{3}{10}:-\frac{1}{100}=\frac{3}{10}~.-\frac{100}{1}=-\frac{300}{10}=-30$

$d)\\ \\(\frac{1}{5}-\frac{1}{2})-(\frac{1}{3}-\frac{1}{4})~.~\frac{2}{5}=\frac{2-5}{10}-\frac{4-3}{12}~.~\frac{2}{5}=-\frac{3}{10}-\frac{1}{12}~.~\frac{2}{5}=\\ \\-\frac{3}{10}-\frac{2}{60}=\frac{-18-2}{60}=-\frac{16}{60}=\frac{4}{15}$

$e)\\ \\-\frac{5}{8}+\frac{1}{4}~.~\frac{1}{5}+\frac{1}{2}=-\frac{5}{8}+\frac{1}{20}+\frac{1}{2}=\\ \\\frac{-25+2+20}{40}=-\frac{3}{40}$