Question

resolva : (40x²-20x-3ax):(-10x)

Answer 1

Seja $\text{q}=\dfrac{40\text{x}^2-20\text{x}-3\text{ax}}{-10\text{x}}$.

Note que, $\dfrac{40\text{x}^2}{-10\text{x}}=-4\text{x}$.

Depois disso, vemos que, $\dfrac{-20\text{x}}{-10\text{x}}=2$.

Logo, $\text{q}=\dfrac{40\text{x}^2-20\text{x}-3\text{ax}}{-10\text{x}}=-4\text{x}+2$.

Escrevemos assim: $40\text{x}^2-20\text{x}-3\text{ax}=(-10\text{x})\cdot\text{q}-3\text{ax}$