Question

Resolva:

2^2x - 12.2^x + 32 = 0

Answer 1

2^2x - 12.2^x + 32 = 0

   - 10.2^x = - 32 (-1)

         10.2^x = 32 
            2^x = 32
                     10
         Log2^x = Log 32/10
    x . log 2 = log 32 - log 10
    x. log 2 = log 2^5 - log10
    x  log2 = 5log2 - log10
     
     x =  5.log2 - 1
                log2