Question

resolução de 2x²+ax=3a²

Answer 1

$2x^2+ax=3a^2\\2x^2+ax-3a^2=0\\\Delta = b^2-4ac\\\Delta = a^2-4\times 2\times (-3a^2)\\\Delta = a^2+24a^2\\\Delta = 25a^2x=\dfrac{-b\pm \sqrt{\Delta}}{2a}\\x=\dfrac{-a\pm \sqrt{25a^2}}{2\times 2}\\x=\dfrac{-a\pm 5a}{4}\\x'=\dfrac{-a+ 5a}{4}=\dfrac{4a}{4}=a\\x''=\dfrac{-a- 5a}{4}=\dfrac{-6a}{4}=-\dfrac{3a}{2}$

Espero ter sido útil