Question

resolava pfv plisss​

Answer 1

$\frac{2^{98}+4^{50}-8^{34}}{2^{99}-32^{20}+2^{101} } =\frac{2^{98}+2^{2.50}-2^{3.34}}{2^{99}-2^{5.20}+2^{101} }=\frac{2^{98}+2^{100}-2^{102}}{2^{99}-2^{100}+2^{101} }=2296$