Question

REPRESENTE NO PLANO CARTESIANO OS SEGUINTES PONTOS
GENTE POR FAVOR ME AJUDEMMMM POIS EU NÃO CONSIGO ....POR FAVORRR GENTE ME AJUDEMMM POR FAVORRRR

Answer 1

$a.A(2;3);B(2,5)\\\\D_{AB}= \sqrt{(x_b-x_a)^2+(y_b-y_a)^2} \to \\ D_{AB}= \sqrt{(2-2)^2+(5-3)^2} \to \\D_{AB}= \sqrt{(0)^2+(2)^2} \to \\D_{AB}= \sqrt{0+4} \to \\D_{AB}= \sqrt{4} \to \\ D_{AB}=2$






$b. A(2;1);B(-2;4)\\\\ D_{AB}= \sqrt{(x_b-x_a)^2+(y_b-y_a)^2} \to \\ D_{AB}= \sqrt{(-2-2)^2+(4-1)^2} \to \\D_{AB}= \sqrt{(-4)^2+(3)^2} \to \\ D_{AB}= \sqrt{16+9} \to \\ D_{AB}= \sqrt{25} \to \\ D_{AB}= 5$






$c.A(0,6);(1;5)\\D_{AB}= \sqrt{(x_b-x_a)^2+(y_b-y_a)^2} \to \\ D_{AB}= \sqrt{(1-0)^2+(5-6)^2} \to \\ D_{AB}= \sqrt{(1)^2+(-1)^2} \to \\ D_{AB}= \sqrt{1+1} \to \\ D_{AB}= \sqrt{2}$






$d.A(6;3);B(2;7)\\\\ D_{AB}= \sqrt{(x_b-x_a)^2+(y_b-y_a)^2} \to \\ D_{AB}= \sqrt{(2-6)^2+(7-3)^2} \to \\ D_{AB}= \sqrt{(-4)^2+(4)^2} \to \\ D_{AB}= \sqrt{16+16} \to \\ D_{AB}= \sqrt{32} \to \\ D_{AB}= \sqrt{2^5} \to \\ D_{AB}= \sqrt{2^2*2^2*2} \to \\ D_{AB}=2*2 \sqrt{2} \to \\ D_{AB}= 4\sqrt{2}$