Question

Represente no plano cartesiano e determine o coeficiente angular (ou declive) da reta que passa pelos pontos a) A(5, 4) e B(3, 2) b) C(4, 2) e D(6, 3) c) E(-2, -1) e F(1, 3) d) G(-3, 2) e H(6, -5) me ajudem por favor :)

Answer 1

$<var>\boxed{m = \frac{\Delta y}{\Delta x}}</var>$

 

a) $<var>A(5,4) \ \ \ \ \ \ B(3,2) \\\\ m = \frac{\Delta y}{\Delta x} = \frac{y_{f}-y_{i}}{x_{f}-x_{i}} = \frac{2-4}{3-5} = \frac{-2}{-2} = \boxed{1}</var>$

 

b) $<var>C(4,2) \ \ \ \ \ \ D(6,3) \\\\ m = \frac{\Delta y}{\Delta x} = \frac{y_{f}-y_{i}}{x_{f}-x_{i}} = \frac{3-2}{6-4} = \boxed{\frac{1}{2}}</var>$

 

c) $<var>E(-2,-1) \ \ \ \ \ \ F(1,3) \\\\ m = \frac{\Delta y}{\Delta x} = \frac{y_{f}-y_{i}}{x_{f}-x_{i}} = \frac{3-(-1)}{1-(-2)} = \frac{3+1}{1+2} = \boxed{\frac{4}{3}}</var>$

 

d) $<var>G(-3,2) \ \ \ \ \ \ H(6,-5) \\\\ m = \frac{\Delta y}{\Delta x} = \frac{y_{f}-y_{i}}{x_{f}-x_{i}} = \frac{-5-2}{6-(-3)} = \frac{-7}{6+3} = \frac{-7}{9} = \boxed{-\frac{7}{9}}</var>$