Question

reponda : 3x^2-11x+10x=0
(FORMULA DE BHASKARA)

Answer 1

3x²-11x+10x=0
3x²-1x=0
Δ=b²-4ac
Δ=(-1)²-4*3*0
Δ=1

x1= -b+raíz de delta
x1= -(-1) + 1
x1= +2

x2= -b -raiz de delta
x2= -(-1) -1
x2= 0