Matemática, perguntado por bianca008santos, 7 meses atrás

Reduza os termos semelhantes nas seguintes expressões algébricas:

a) (3a + 2m ) – [ ( a – 2m) – (6a + 2m)] =


b) 7x³- { 3x² - x – [ 2x – { 5x³ - 6x² ) – 4x ]} =


c) 2y – { 3y + [4y – (y – 2x) + 3x ] – 4x } + 2x =


d) 8y + { 4y – [ 6x – y- (4x – 3y) – y ] – 2x } =


e) 4x – { 3x + [ 4x – 3y – (6x – 5y ) – 3x ] – 6y}=


f) 3x – { 3x – [3x – (3x –y) – y ] – y} - y =​

Soluções para a tarefa

Respondido por uchihayasmin2307
4

Resposta:

A)

(3a+2m)—[(a—2)—(6a+2m)]

= (3a+2m)—[(a—2—6a—2m)]

= (3a+2m)—(—5a—2m—2)

= 3a+2m+5a+2m+2

= 8a+4m+2

B)

7x³—[3x²—x{2x—(5x³—6x²)—4}]

= 7x³—[3x²—x{2x—5x³+6x²—4}]

= 7x³—(3x²—2x²+5x⁴—6x³+4x)

= 7x³—(x²+5x⁴—6x³+4x)

= 7x³—x²—5x⁴+6x³—4x

= —5x⁴+13x³—x²—4x

C)

2y—[3y+{4y—(y—2x)+3x}—4x]+2x

= 2y—[3y+{4y—y+2x+3x}—4x]+2x

= 2y—[3y+{3y+5x}—4x]+2x

= 2y—(3y+3y+5x—4x)+2x

= 2y—(6y+x)+2x

= 2y—6y—x+2x

= —4y + x

D)

8y+[4y—{6x—y—(4x—3y)—y}—2x]

= 8y+[4y—{6x—y—4x+3y—y}—2x]

= 8y+[4y—(2x+y)—2x]

= 8y+(4y—2x—y—2x)

= 8y+(3y—4x)

= 8y+3y—4x

= 4x+3y

E)

4x—[3x+{4x—3y—(6x—5y)—3x}—6y]

= 4x—[3x+{4x—3y—6x+5y—3x}—6y]

= 4x—[3x+(4x—6x—3x—3y+5y)—6y]

= 4x—[3x+(—5x+2y)—6y]

= 4x—(3x—5x+2y—6y)

= 4x—(—2x—4y)

= 4x+2x+4y

= 6x+4y

F)

3x—[3x—{3x—(3x—y)—y}—y]—y

= 3x—[3x—{3x—3x+y—y}—y]—y

= 3x—[3x+y]—y

= 3x—3x—y—y

= —2y

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