Question

reduza os monômios semelhantes d) - ¾ ax + ⅓ ax - ½ ax

Answer 1

Simplificando:

$\mathsf{=-\dfrac{3}{4}ax+\dfrac{1}{3}ax-\dfrac{1}{2}ax}\\\\\\\mathsf{=-\dfrac{3ax}{4}+\dfrac{ax}{3}-\dfrac{ax}{2}}\\\\\\\mathsf{=-\dfrac{3\cdot 3ax}{3\cdot 4}+\dfrac{4\cdot ax}{4\cdot 3}-\dfrac{6\cdot ax}{6\cdot 2}}\\\\\\\mathsf{=-\dfrac{9ax}{12}+\dfrac{4ax}{12}-\dfrac{6ax}{12}}\\\\\\\mathsf{=\dfrac{-9ax+4ax-6ax}{12}}\\\\\\\boxed{\mathsf{-\dfrac{11ax}{12}}}\: \: \checkmark$