Question

reduza a forma normal (t-1)2+(T+2)2-9=0

Answer 1

(t-1)2+(T+2)2-9=0

t² - 2t + 1 + t² + 4t + 4 - 9 = 0

2t² + 2t - 4 = 0(: 2) ==> t² + t - 2 = 0

Δ = 1² - 4.1.2 = 1 +8 = 9

x = - 1+/- 3 
           2

x1 = - 1+3 ==>x1= 1
            2

x2 = - 1-3 ==>x1= - 2
            2