Question

reduza a CNTP 38L de cloro que foram medidos a 127°c e a uma pressão de 720mmHg.

Answer 1

$P1=720mmHg=0,95 atm~~~~~~~~~~~~~~~~P2=1atm \\ T1=127+273= 400K~~~~~~~~~~~~~~~~~~~~~T2=273K \\ V1=38L~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~V2=x \\ \\ \\ \frac{P1*V1}{T1}= \frac{P2*V2}{T2} \\ \\ \frac{0,95*38}{400}= \frac{1*X}{273} \\ \\ 9855,3=400X \\ \\ X= \frac{9855,3}{400} \\ \\ X=24,64L$