Realize a derivada primeira da função........
Anexos:
![](https://pt-static.z-dn.net/files/d21/f9a2cd0a2a18211c7310fe33dc5ca63c.png)
Soluções para a tarefa
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Boa tarde!
Solução!
![y=2x.sen( x^{2} )\\\\
u=2x~~~~~v=sen( x^{2} )\\\\\\
u'=2~~~~~v'=2xcos( x^{2} )
y=2x.sen( x^{2} )\\\\
u=2x~~~~~v=sen( x^{2} )\\\\\\
u'=2~~~~~v'=2xcos( x^{2} )](https://tex.z-dn.net/?f=%0Ay%3D2x.sen%28+x%5E%7B2%7D+%29%5C%5C%5C%5C%0A%0A%0Au%3D2x%7E%7E%7E%7E%7Ev%3Dsen%28+x%5E%7B2%7D+%29%5C%5C%5C%5C%5C%5C%0Au%27%3D2%7E%7E%7E%7E%7Ev%27%3D2xcos%28+x%5E%7B2%7D+%29%0A)
![y'=u'.v+v'.u\\\\\\
substituindo~~os~~dados~~acima!\\\\\\
y'=2.sen( x^{2} )+2xcos(x^{2}) .(2x)\\\\\\
y'=2.sen( x^{2} )+4 x^{2} cos(x^{2})\\\\\\ y'=u'.v+v'.u\\\\\\
substituindo~~os~~dados~~acima!\\\\\\
y'=2.sen( x^{2} )+2xcos(x^{2}) .(2x)\\\\\\
y'=2.sen( x^{2} )+4 x^{2} cos(x^{2})\\\\\\](https://tex.z-dn.net/?f=y%27%3Du%27.v%2Bv%27.u%5C%5C%5C%5C%5C%5C%0Asubstituindo%7E%7Eos%7E%7Edados%7E%7Eacima%21%5C%5C%5C%5C%5C%5C%0Ay%27%3D2.sen%28+x%5E%7B2%7D+%29%2B2xcos%28x%5E%7B2%7D%29+.%282x%29%5C%5C%5C%5C%5C%5C%0Ay%27%3D2.sen%28+x%5E%7B2%7D+%29%2B4+x%5E%7B2%7D+cos%28x%5E%7B2%7D%29%5C%5C%5C%5C%5C%5C)
![\boxed{Resposta:y=2x.sen( x^{2} )=y'=2.sen( x^{2} )+4 x^{2} cos(x^{2})} \boxed{Resposta:y=2x.sen( x^{2} )=y'=2.sen( x^{2} )+4 x^{2} cos(x^{2})}](https://tex.z-dn.net/?f=%5Cboxed%7BResposta%3Ay%3D2x.sen%28+x%5E%7B2%7D+%29%3Dy%27%3D2.sen%28+x%5E%7B2%7D+%29%2B4+x%5E%7B2%7D+cos%28x%5E%7B2%7D%29%7D)
![\boxed{Resposta:Alternativa~~A} \boxed{Resposta:Alternativa~~A}](https://tex.z-dn.net/?f=%5Cboxed%7BResposta%3AAlternativa%7E%7EA%7D)
Boa tarde!
Bons estudos!
Solução!
Boa tarde!
Bons estudos!
073841:
obrigado, sera que não poderia me ajudar nessa outra http://brainly.com.br/tarefa/5143799
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