Question

Raiz quadrada de (x^2-10x+25) - Raiz quadrada de (x^2+10x+25)

Answer 1

X² - 10x + 25 = 0

Delta = b² - 4ac

Delta = (-10)² - 4(1)(25)

Delta = 100 - 100

Delta = zero

X = (-b +- raiz delta) / 2a

X = (10 +- 0) / 2

x' = (10 + 0) / 2 = 10/2 = 5

x" = (10 - 0) / 2 = 10/2 = 5